Cart

Your cart is empty

⭐️⭐️⭐️⭐️⭐️ Our sustainable cashmere has thousands of 5-star reviews

Brand New Burberry Equine Green and White Silk Scarf

£285.00

With its original creases this is a brand new scarf without tags from Burberry in silk twill with hand rolled edges. Made in Italy and measuring 36 inches square.

Easy returns & free UK shipping over £75

Brand New Burberry Equine Green and White Silk Scarf

£285.00

#1

Immaculate second hand cashmere, keeping you warm without costing the Earth..

#2

The UK's largest selection of second hand cashmere.

#3

Breathing new life into over 30,000 cashmere jumpers every year.

Meet the founder

Free delivery when you spend £75

and free returns when you exchange!

Immaculate Second hand cashmere

Keeping you warm without costing the Earth.

The UK's largest selection of second hand cashmere

There's something for everyone.

A small family business you can trust

We pride ourselves on our customer service.

document.addEventListener("DOMContentLoaded", function () { if (document.body.classList.contains('collection-women')) { const container = document.querySelector('[data-id="main-collection-product-grid"], .product-grid, .grid, .collection__products'); // Try all common selectors if (!container) return; const items = Array.from(container.children); // Fisher-Yates shuffle for (let i = items.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [items[i], items[j]] = [items[j], items[i]]; } // Re-append in new order items.forEach(item => container.appendChild(item)); } }); document.addEventListener("DOMContentLoaded", function () { if (document.body.classList.contains('collection-women')) { const container = document.querySelector('[data-id="main-collection-product-grid"], .product-grid, .grid, .collection__products'); // Try all common selectors if (!container) return; const items = Array.from(container.children); // Fisher-Yates shuffle for (let i = items.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [items[i], items[j]] = [items[j], items[i]]; } // Re-append in new order items.forEach(item => container.appendChild(item)); } });